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24x^2+46x+7=0
a = 24; b = 46; c = +7;
Δ = b2-4ac
Δ = 462-4·24·7
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(46)-38}{2*24}=\frac{-84}{48} =-1+3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(46)+38}{2*24}=\frac{-8}{48} =-1/6 $
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